- Consider the following reaction in aqueous solution,
5Br-(aq) + BrO3-(aq)
+ 6H+(aq) --> 3Br2(aq) + 3H2O(l)
If the rate of appearance of Br2 at a
particular moment during the reaction is 0.025 M s-1,
what is the rate of disappearance (in M s-1)
of Br- at that moment?
- Consider the following reaction at 25oC,
(CH3)3COH(l) + HCl(aq)
--> (CH3)3CCl(l) + H2O(l)
The experimentally determined rate law for this
reaction indicates that the reaction is first-order in (CH3)3COH
and that the reaction is first-order overall. Which of
the following would produce an increase in the rate of
this reaction?
- increasing the concentration of (CH3)3COH
- increasing the concentration of HCl
- decreasing the concentration of HCl
- decreasing the concentration of (CH3)3CCl
- It is impossible to tell.
- A certain first-order reaction has a rate constant, k,
equal to 2.1 x 10-5 s-1 at 355 K.
If the activation energy for this reaction is 135 kJ/mol,
calculate the value of the rate constant (in s-1)
at 550 K.
- Which of the following influences the rate of a chemical
reaction performed in solution?
- temperature
- activation energy
- presence of a catalyst
- concentrations of reactants
- All of the above influence the rate.
- The two diagrams below represent snapshots of a very
small portion of a first-order reaction in which A
molecules are being converted to B molecules (A --> B):
Which of the following diagrams represents a snapshot
of a very small portion of this system at t = 3 min?
- Laughing gas, N2O, can be prepared (ha, ha!)
from H2 and NO:
H2(g)
+ 2 NO(g) --> N2O(g) + H2O(g)
A study of initial concentration (ha, ha!) versus
initial rate at a certain temperature yields the
following data for this reaction (ha, ha!):
[H2], M |
[NO], M |
initial rate, M s-1 |
0.1000 |
0.5000 |
2.560 x 10-6 |
0.2000 |
0.3000 |
1.843 x 10-6 |
0.1000 |
0.3000 |
9.216 x 10-7 |
0.2000 |
0.6000 |
7.373 x 10-6 |
Which of the following is the correct
rate law for this reaction (ha, ha!)?
- Rate = k[H2][NO]2
- Rate = k[H2][NO]
- Rate = k[NO]2
- Rate = k[H2]2
- Rate = k
- Iodine-131, a radioactive isotope of iodine, is used
medicinally as a radiotracer for the diagnosis and
treatment of illnesses associated with the thyroid gland.
The half-life of iodine-131 is 7.0 x 105
seconds. If a patient is given 0.45 g of iodine-131,
calculate how long it would take (in seconds) for 90.0%
of the iodine-131 to decay. Recall: radioactive decay
is a first-order process.
- Consider a reaction which is first-order in A and
first-order in B,
A + B --> Products Rate = k[A][B]
What are the relative rates of this reaction in the
vessels shown below. Note: each vessel has the same
volume.
- III > I = IV > II
- I > III > II > IV
- IV > II > III > I
- II > IV > I > III
- III > I > IV > II
- The complex ion, [Cr(NH3)5Cl]2+,
reacts with OH- ion in aqueous solution,
[Cr(NH3)5Cl]2+(aq)
+ OH-(aq) --> [Cr(NH3)5(OH)]2+(aq)
+ Cl-(aq)
The following data were obtained for this reaction at
25oC,
time, min |
[Cr(NH3)5Cl]2+,
M |
0 |
1.00 |
6 |
0.657 |
12 |
0.432 |
18 |
0.284 |
24 |
0.186 |
30 |
0.122 |
36 |
0.0805 |
The order of the reaction with respect
to the [Cr(NH3)5Cl]2+
ion is:
- zero order
- first order
- second order
- third order
- fourth order
- A student determined the value of the rate constant, k,
for a chemical reaction at several different temperatures.
Which of the following graphs of the student's data would
give a straight line?
- k versus T
- k versus (1/T)
- ln k versus (1/T)
- ln k versus T
- ln k versus Ea
- In the experiment, "How Can Spectrophotometric
Methods Be Used to Determine the Order of a Chemical
Reaction", it is necessary to remove invalid data
points towards the end of the reaction. Which of the
following statements best explains why this is necessary?
- The Spectronic 20 becomes unstable towards the
end of the reaction.
- Towards the end of the reaction, the temperature
of the solution is significantly different than
the initial temperature of the solution.
- Towards the end of the reaction, the
concentrations of the reactants are so high that
it is difficult to measure them accurately.
- Towards the end of the reaction, the
concentrations of the products are sufficiently
high that the reverse reaction competes with the
forward reaction.
- None of these.
The next two questions are about this reaction:
2N2O5 (g) <==>
4NO2 (g) + O2 (g)
- The rate law for the above reaction is:
- rate = k [N2O5]2
- rate = [N2O5]2
- rate = k [N2O5]2
/ [NO2]4 [O2]1
- rate = k [N2O5]x
- rate = [N2O5]x
- If the instantaneous rate of appearance of NO2
(g) is 0.0400 M/s at some moment in time, what is the
rate of disappearance of N2O5 (g)
in M/s ?
- The rate laws for certain enzyme-activated reactions in
your body have a specific rate constant k, with units of
M/s. What is the overall order of these reactions?
- 0
- 1
- 2
- 3
- Cannot be determined.
The next two questions are about this reaction:
2NO(g) + Cl2(g) <==> 2NOCl(g)
- The rate law for the above reaction has been determined
to be
rate = k[NO][Cl2].
What is the overall order of the reaction?
- 0
- 1
- 2
- 3
- Cannot be determined.
- A mechanism involving the following steps has been
proposed for the above reaction:
(1) |
NO(g) + Cl2(g) -->
NOCl2(g) |
(2) |
NOCl2(g) + NO(g) -->
2NOCl(g) |
Based on the rate law given in the
preceding problem, which step is the rate-limiting step?
- Step (1)
- Step (2)
- Both Steps (1) & (2)
- Either Steps (1) or (2)
- Consider the following reaction in aqueous solution,
I- (aq) + OCl- (aq)
-> IO- (aq) + Cl- (aq)
and the following initial concentration and initial
rate data for this reaction:
[I-], M |
[OCl-], M |
initial rate, M s-1 |
0.1000 |
0.0500 |
3.05 x 10-4 |
0.2000 |
0.0500 |
6.10 x 10-4 |
0.3000 |
0.0100 |
1.83 x 10-4 |
0.3000 |
0.0200 |
3.66 x 10-4 |
Which of the following is the correct
rate law for this reaction?
- Rate = k[I-]
- Rate = k[OCl-]
- Rate = k[I-]2
- Rate = k[I-][OCl-]
- Rate = k[I-]2[OCl-]
- Which of the following statements best describes how the
"Method of Initial Rates" is used to measure
the initial rate of an equilibrium reaction?
- The rate of the reaction is measured when the
reaction is very close to equilibrium.
- The rate of the reaction is measured immediately
after the reaction is started.
- The rate of the reaction is measured when the
reaction is about one-half complete.
- The rate of the reaction is measured after five
half-lives.
- The rate of an equilibrium reaction cannot be
measured using this method.
- Which of the following are the correct units for the rate
constant, k, for a zero-order reaction?
- M s-1
- M-1 s-1
- M-2 s-1
- M-3 s-1
- M
- Which of the following statements is TRUE?
- The existence of certain intermediates in a
reaction mechanism can sometimes be proven
because intermediates can sometimes be trapped
and identified.
- Intermediates in a reaction mechanism cannot be
isolated because they do not have finite
lifetimes.
- Reaction mechanisms cannot have any more than one
intermediate.
- Intermediates in a reaction mechanism appear in
the overall, balanced equation for the reaction.
- None of the above statements is TRUE.
- Which of the following statements best describes how a
catalyst works?
- A catalyst changes the potential energies of the
reactants and products.
- A catalyst decreases the temperature of the
reaction which leads to a faster rate.
- A catalyst lowers the activation energy for the
reaction by providing a different reaction
mechanism.
- A catalyst destroys some of the reactants, which
lowers the concentration of the reactants.
- A catalyst raises the activation energy for the
reaction which produces a faster rate.
- In terms of the "Collision Theory of Chemical
Kinetics", the rate of a chemical reaction is
proportional to:
- the change in free energy per second.
- the change in temperature per second.
- the number of collisions per second.
- the number of product molecules.
- none of the above.
- Nitrogen monoxide, NO, reacts with hydrogen, H2,
according to the following equation:
2
NO (g) + 2 H2 (g) -> N2 (g) + 2
H2O (g)
If the mechanism for this reaction were,
2NO(g) + H2(g) ->
N2(g) + H2O2(g) |
slow |
H2O2(g)
+ H2(g) -> 2H2O(g) |
fast |
which of the following rate laws would
we expect to obtain experimentally?
- Rate = k[H2O2][H2]
- Rate = k[NO]2[H2]
- Rate = k[NO]2[H2]2
- Rate = k[NO][H2]
- Rate = k[N2][H2O2]
- Consider the following reaction in aqueous solution,
5 Br- (aq) + BrO3-
(aq) + 6 H+ (aq) -> 3 Br2 (aq) +
3 H2O (l)
If the rate of disappearance of Br- (aq) at
a particular moment during the reaction is 3.5 x 10-4
M s-1, what is the rate of appearance of Br2
(aq) at that moment?
- Consider the following gas-phase reaction,
2 HI (g) -> H2 (g) + I2
(g)
and the following experimental data obtained at 555 K,
[HI], M |
rate, M s-1 |
0.0500 |
8.80 x 10-10 |
0.1000 |
3.52 x 10-9 |
0.1500 |
7.92 x 10-9 |
What is the order of the reaction with
respect to HI (g)?
- Radioactive phosphorus is used in the study of
biochemical reaction mechanisms. The isotope phosphorus-33
decays by first-order kinetics with a half-life of 14.3
days. If a chemist initially has a 7.5 M solution of pure
phosphorus-33, calculate the concentration (in M) of
phosphorus-33 in the solution after 2.4 days.
- Hydrogen iodide, HI, decomposes in the gas phase to
produce hydrogen, H2, and iodine, I2:
2 HI (g) -> H2 (g) + I2
(g)
The value of the rate constant, k, for this reaction
was measured at several different temperatures and the
data are shown below:
temperature, K |
k, M-1 s-1 |
555 |
6.23 x 10-7 |
575 |
2.42 x 10-6 |
645 |
1.44 x 10-4 |
700 |
2.01 x 10-3 |
Calculate the value of the activation
energy (in kJ/mol) for this reaction.
- Listed below are some statements that pertain to chemical
kinetics. For each statement, first decide whether the
statement is TRUE or FALSE. If the
statement is FALSE, briefly explain why the
statement is FALSE. If the statement is TRUE,
you do not need to provide any additional explanation.
- Rate laws for chemical reactions can be
determined from the stoichiometry of the overall
balanced equation.
- The rate of a chemical reaction that occurs in
solution depends on the concentration, the
temperature and the viscosity of the solvent.
- The "Method of Initial Rates" cannot be
used for equilibrium reactions.
- Experimentally, transition states can sometimes
be trapped or isolated whereas intermediates
cannot be either trapped or isolated.
- Consider the following reaction,
2 ClO2
(aq) + 2 OH- (aq) -> ClO3-
(aq) + ClO2- (aq) + H2O
(l)
Write an expression that describes the relationship
between the rates of disappearance of ClO2 and
OH- and the rates of appearance of ClO3-,
ClO2- and H2O.
- A Chemistry 116 student was charged with the task of
determining the activation energy, Ea, for a
particular first-order reaction. The student measured the
value of the rate constant for this reaction at several
temperatures and obtained the following data:
k, s-1 |
T, K |
3.94 x 10-4 |
384 |
1.17 x 10-3 |
397 |
5.26 x 10-2 |
447 |
4.63 x 10-1 |
481 |
- Nitrogen monoxide, NO, reacts with ozone, O3,
to produce nitrogen dioxide, NO2, and oxygen,
O2:
NO (g) + O3
(g) -> NO2 (g) + O2
(g)
The experimentally determined rate law for this
reaction is: Rate = k[O3]. Consider the
following proposed mechanism for this reaction:
Step 1: |
O3 (g) ->
O2 (g) + O (g) |
fast |
Step 2: |
NO (g) + O (g) ->
NO2 (g) |
slow |
This proposed mechanism is NOT
an acceptable possibility for this reaction. Briefly
explain why this mechanism is not acceptable. ALSO,
identify the rate-determining step and any intermediates
in this proposed mechanism.
- Using the information in the previous question, and your
knowledge about reaction mechanisms, write an acceptable
mechanism for the reaction described in the previous
question.
- In many kinetics studies, the rate of the reaction is
determined almost immediately after the reactants are
mixed. The BEST reason for doing this is:
- The reaction proceeds faster as time increases.
- Intermediates are easier to detect.
- The reaction proceeds slower as time increases.
- Reverse reactions are avoided.
- The concentrations of the reactions hasn't
changed much.
USE THE FOLLOWING DATA FOR THE NEXT THREE (3)
QUESTIONS.
Nitric oxide gas reacts with chlorine gas according to
the equation,
2 NO + Cl2 -> 2 NOCl
The following data were obtained for this reaction:
initial [NO] |
initial [Cl2] |
initial rate |
0.50 M |
0.50 M |
1.19 mol/L hr |
1.00 |
0.50 |
4.79 |
1.00 |
1.00 |
9.59 |
1.50 |
1.50 |
32.27 |
- Which of the following rate laws is consistent with these
data?
- Rate = k[NO]
- Rate = k[NO][Cl2]1/2
- Rate = k[NO][Cl2]
- Rate = k[NO]2[Cl2]
- Rate = k[NO]2[Cl2]2
- What is the OVERALL order of the reaction of NO
with Cl2?
- 1
- 1.5
- 2
- 3
- 4
- What is the value of the rate constant for the reaction
of NO with Cl2?
- 2.38
- 3.35
- 4.76
- 9.52
- 19.04
- For the chemical reaction 2 NO2(g) -> 2 NO
(g) + O2(g), a plot of [NO2] vs.
time gives a curved line, a plot of 1/[NO2]
gives a straight line with a positive slope, and a plot
of ln[NO2] vs. time gives a curved line. What
is the order of reaction?
- Zero order.
- First order.
- Second order.
- A fractional order.
- Impossible to determine from this data.
- Consider the following reaction:
2 NOBr(g)
-> 2 NO(g) + Br2(g)
The reaction is known to be second order with k = 0.80
L/mol s. If you start with a concentration of 0.086 mol/L
of NOBr, what will be its concentration after 22 seconds?
- 2.0 x 10-9 mol/L
- 5.4 x 10-2 mol/L
- 3.4 x 10-2 mol/L
- 8.7 x 10-1 mol/L
- 1.8 x 101 mol/L
- Carbon-14 decays by a first order process and has a half
life of 5,730 years. Assuming some charcoal from a
campfire 29,000 years old was found, what fraction of the
original carbon-14 would remain today?
- 0.000121
- 0.0300
- 0.197
- 3.51
- 33.4
- In terms of the collision model of kinetics, which of the
following factors BEST accounts for the fact that
not all collisions result in a reaction?
- The temperature of the system.
- The orientation of the molecules at the moment of
collision.
- The energy with which the collisions occur.
- The activation energy of the complex.
- All of these factors are important.
- The reaction 2 NO2 + O3 -> N2O5
+ O2 obeys the rate law,
Rate
= kobserved[NO2][O3]
Which of the following mechanisms is consistent with
this experimental rate law?
(a) NO2 + NO2 <=> N2O4 (fast equilibrium)
N2O4 + O3 -> N2O5 + O2 (slow)
(b) NO2 + O3 -> NO5 (fast)
NO5 + NO5 -> N2O5 + 5/2 O2 (slow)
(c) NO2 + O3 -> NO3 + O2 (slow)
NO3 + NO2 -> N2O5 (fast)
(d) NO2 + NO2 -> N2O2 + O2 (slow)
N2O2 + O3 -> N2O5 (fast)
(e) None of these mechanisms are possible.
- According to the collision model of kinetics, certain
activation energy must be overcome before a reaction can
proceed. Based on the data given below, what is a
reasonable estimate of the activation energy for the
decomposition of NOCl?
2 NOCl(g) ->
2 NO(g) + Cl2(g)
temperature (K) |
rate constant, k (L/mol s) |
400 |
6.6 x 10-4 |
500 |
2.9 x 10-1 |
600 |
1.63 x 101 |
- 1.00 x 102 J/K mol
- 1.23 x 103 J/K mol
- 1.05 x 105 J/K mol
- 1.34 x 106 J/K mol
- 1.22 x 108 J/K mol
- The reaction rates for many spontaneous reactions are
actually very slow. Which of the following is the best
explanation for this observation?
- Kp for the reaction = 0.
- The activation energy is high.
- The standard free energy change for the reaction
is > 0.
- These reactions are endothermic.
- The standard entropy change is < 0.
- We observed a demonstration of the reaction: H2O2
-> H2O + 1/2 O2 to which I-
was added. A large foaming mass of bubbles was formed.
The following mechanism has been proposed for this
reaction:
H2O2 + I-
-> H2O + IO- |
(slow) |
H2O + IO-
-> H2O + 1/2 O2 + I- |
(fast) |
The function of the I- in
this reaction is to:
- Raise the
H of the products.
- Lower the
G between reactants and products.
- Increase the concentration of products.
- Lower the activation energy.
- Raise the
S of the reactants.
- In the lab, a chemist measured the rate constant, k,
at 25oC for four different second-order
reactions which were all performed in the same solvent.
Which of the four reactions was the fastest reaction?
- Reaction 1: k = 2.9 x 10-7 M-1
s-1
- Reaction 2: k = 4.2 x 10-5 M-1
s-1
- Reaction 3: k = 7.8 x 102 M-1
s-1
- Reaction 4: k = 3.6 x 106 M-1
s-1
- There is insufficient information to answer this
question.
- In lecture, we studied the decomposition of hydrogen
peroxide, H2O2, in aqueous solution
to produce water, H2O, and oxygen gas, O2:
2 H2O2 (aq) ->
2 H2O (l) + O2 (g)
If the average rate of disappearance of H2O2
over a certain time interval is 6.80 x 10-5 M
s-1, what is the average rate of appearance of
O2 during this same time interval?
- 4.62 x 10-9 M s-1
- 3.40 x 10-5 M s-1
- 6.80 x 10-5 M s-1
- 1.36 x 10-4 M s-1
- There is insufficient information to answer this
question.
- In 1918, Fritz Haber, a German chemist, received the
Nobel prize in chemistry for his work on developing a
direct synthesis of ammonia on a commercial scale.
Ammonia, which is used heavily by farmers as a
fertilizer, is produced commercially by the Haber process:
N2 (g) + 3 H2 (g)
-> 2 NH3 (g)
Commercially, this reaction is performed at high
temperature and in the presence of a heterogeneous
catalyst (iron oxide) to increase the rate of the
reaction. Which of the following "forms" of
iron oxide would be the most effective for increasing the
rate of the reaction?
- 1 g of iron oxide pellets (10 small spherical
pellets)
- 1 g of iron oxide pellets (1 large spherical
pellet)
- 1 g of iron oxide powder
- 1 g of iron oxide wire
- 1 g of iron oxide sitting on a table outside of
the reaction vessel
- Aspirin, C9H8O4, slowly
decomposes at room temperature by reacting with water in
the atmosphere to produce acetic acid, C2H4O2,
and 2-hydroxybenzoic acid, C7H6O3
(this is why old bottles of aspirin often smell like
vinegar):
C9H8O4
(aspirin) + H2O -> C2H4O2
(acetic acid) + C7H6O3
Consider the following initial concentration and
initial rate data for this reaction:
[Aspirin], M |
[H2O], M |
initial rate, M s-1 |
0.0100 |
0.0200 |
2.4 x 10-13 |
0.0100 |
0.0800 |
9.6 x 10-13 |
0.0300 |
0.0200 |
7.2 x 10-13 |
0.0200 |
0.0300 |
7.2 x 10-13 |
Which of the following is the correct
rate law for this reaction?
- Rate = k[aspirin]
- Rate = k[aspirin][H2O]
- Rate = k[H2O]
- Rate = k[aspirin]2[H2O]
- Rate = k[aspirin]2[H2O]2
- Using the "Method of Initial Rates" in kinetic
studies is advantageous because it allows us to measure
the initial rates for which of the following types of
reactions?
- spontaneous reactions
- reactions with large activation energies
- equilibrium reactions
- reactions carried out at low temperature
- all of the above
- The radioactive element, thallium-201, is used
medicinally as a radiotracer to study damage in heart
tissue. If a patient is injected with a 0.950 g dose of
pure thallium-201, calculate the amount of time that
would be required for the amount of thallium-201 in the
patient's body to reach 0.0500 g. Thallium-201 decays by
a first-order process with a half-life, t1/2 =
73.0 hours.
- 0.040 hours
- 5.70 hours
- 113 hours
- 226 hours
- 310 hours
- Consider the gas-phase decomposition of hydrogen iodide,
HI, to produce hydrogen, H2, and iodine, I2,
2 HI (g) -> H2 (g) + I2
(g)
and the following data which were obtained at a
temperature of 282oC:
time, h |
[HI] |
1/[HI] |
ln [HI] |
0 |
0.900 |
1.111 |
-0.105 |
200 |
0.733 |
1.364 |
-0.311 |
400 |
0.618 |
1.618 |
-0.481 |
600 |
0.534 |
1.873 |
-0.627 |
Which of the following statements is TRUE?
- The decomposition of HI is a first-order process.
- The decomposition of HI is a zero-order process.
- A plot of ln [HI] versus time is linear with a
slope of -k.
- A plot of 1/[HI] versus time is linear with a
slope of +k.
- The half-life for this reaction is 180 hours.
- For a certain reaction that follows second-order
kinetics,
A + B -> C + D + E
the value of the rate constant, k, was measured
at several different temperatures and the data are shown
below:
temperature, oC |
k, M-1 s-1 |
100 |
6.264 |
150 |
45.464 |
200 |
217.008 |
250 |
768.232 |
Calculate the value of the activation
energy, Ea, for this reaction.
- 13.9 kJ
- 27.4 kJ
- 52.0 kJ
- 97.8 kJ
- 143 kJ
- Chlorine, Cl2, reacts with hydrogen sulfide, H2S,
in aqueous solution to produce solid sulfur and hydrogen
chloride, HCl:
Cl2 (aq) + H2S
(aq) -> S (s) + 2 HCl (aq)
The rate law for this reaction is found to be: Rate =
k[Cl2][H2S]. Which of the following
is an acceptable possibility for the mechanism of this
reaction?
(a) Cl2 --> Cl+ + Cl- slow
Cl- + H2S --> HCl + HS- fast
Cl+ + HS- --> HCl + S fast
(b) Cl2 + H2S --> HCl + Cl+ + HS- slow
Cl+ + HS- --> HCl + S fast
(c) Cl2 --> Cl + Cl fast
Cl + H2S --> HCl + HS fast
HS + Cl --> HCl + S slow
(d) All of these mechanisms are acceptable possibilities.
(e) None of these mechanisms are acceptable possibilities.
- A "diffusion-controlled" reaction is a reaction
in which all collisions between the reacting species lead
to products (these reactions are called "diffusion-controlled"
because the rate is controlled only by how fast the
reactant molecules can "diffuse" together). In
aqueous solution at 25oC, the reaction of a
strong acid, H3O+, with a strong
base, OH-, is an example of this type of
reaction. The rate constant, k, for this reaction
is 1.4 x 1011 M-1 s-1,
H3O+ (aq) + OH-
(aq) -> 2 H2O (l)
Which of the following statements is most likely TRUE?
- Increasing the temperature would have no effect
on the rate of this reaction.
- The activation energy for this reaction must be
very large.
- The rate of this reaction would be independent of
the concentrations of H3O+
and OH-.
- The rate constant for this reaction would be
different if the reaction were carried out in a
more viscous solvent than water.
- None of the above.
- Consider the following gas-phase reaction,
Cl2 (g) + 3 F2 (g) ->
2 ClF3 (g)
Write an expression that describes the relationship
between the rate of disappearance of Cl2, the
rate of disappearance of F2 and the rate of
appearance of ClF3.
- In lecture, we used the reaction of permanganate ion, MnO4-,
with oxalic acid, H2C2O4,
to study the effects of several factors upon the rate of
this reaction (this was the solution that went from
purple to colorless):
2 MnO4-
(aq) + 5 H2C2O4 (aq) + 6
H+ (aq) -> 2 Mn2+ (aq) + 10 CO2
(g) + 8 H2O (l)
Write the general form of the differential rate law
for this reaction.
- Consider the following reaction:
2 ClO2
(aq) + 2 OH- (aq) -> ClO3-
(aq) + ClO2- (aq) + H2O
(l)
and the following initial rate data:
[ClO2], mol/L |
[OH-], mol/L |
initial rate, mol/L s |
0.0500 |
0.100 |
5.77 x 10-2 |
0.100 |
0.100 |
2.32 x 10-1 |
0.100 |
0.050 |
1.15 x 10-1 |
- Determine the order of each reactant and write
the differential rate law for this reaction.
- Calculate the value of the rate constant,k, for
this reaction. Be sure to include the appropriate
units for the rate constant!
- What is the overall order for this reaction?
- Describe what would happen to the rate of this
reaction if we tripled the concentration of ClO2
and doubled the concentration of OH-.
- Homes in certain parts of the country contain high levels
of the radioactive isotope, radon-222. Radon-222 decays
by first-order kinetics with a half-life of 3.82 days.
Calculate how long it would take for 95% of a sample of
radon-222 to decay.
- Using the Collision Model of Chemical Kinetics, describe
what requirements must be met for a reaction to occur
between two colliding reactant molecules.
- Consider the hydrogenation of ethylene, C2H4,
using the catalyst platinum oxide, PtO2, to
produce ethane, C2H6:
C2H4 (g) + H2
(g) -> C2H6 (g)
This is an example of heterogeneous catalysis which
often involves gaseous reactants being adsorbed on the
surface of a solid catalyst (i.e., PtO2). The
rate of hydrogenation of ethylene on the surface of the
PtO2 catalyst follows first-order
kinetics for low concentrations of ethylene.
However, as the concentration of ethylene is increased,
the hydrogenation reaction becomes zero-order.
Explain why the hydrogenation reaction in the presence of
the heterogeneous catalyst PtO2 should be zero-order
at high concentrations of ethylene.
- Consider the following gas-phase reaction between
hydrogen, H2, and iodine, I2, to
produce hydrogen iodide, HI:
H2
(g) + I2 (g) -> 2 HI (g)
The values for the rate constant, k, for this
reaction are 2.45 x 10-4 L/mol s at 302oC
and 0.950 L/mol s at 508oC.
- Calculate the value of the activation energy for
this reaction.
- Calculate the value of the rate constant at 434oC.
- Nitrogen dioxide, NO2 reacts with carbon
monoxide, CO, to form nitric oxide, NO, and carbon
dioxide, CO2:
NO2
(g) + CO (g) -> NO (g) + CO2 (g)
The experimentally determined rate law for this
reaction is: Rate = k[NO2]2.
A proposed mechanism for this reaction is shown below.
Step 1: |
NO2 (g) + NO2
(g) -> NO3 (g) + NO (g) |
slow |
Step 2: |
NO3 (g) + CO (g) ->
NO2 (g) + CO2 (g) |
fast |
Determine whether this is a reasonable
mechanism for this reaction and identify the rate-determining
step and any intermediates in this proposed mechanism. Be
sure to explain your reasoning.
- The following data were collected for the reaction
between hydrogen (H2) and nitric oxide (NO) at
700oC,
2H2(g) + 2NO(g)
--> 2H2O(g) + N2(g)
experiment |
[H2], M |
[NO], M |
initial rate, M s-1 |
1 |
0.010 |
0.025 |
2.4 x 10-6 |
2 |
0.0050 |
0.025 |
1.2 x 10-6 |
3 |
0.010 |
0.0125 |
6.0 x 10-7 |
What is the overall order of this
reaction?
- 0
- 1
- 2
- 3
- 4
- The reaction in which NO2 forms a dimer,
2NO2(g) <==> N2O4(g)
has the following experimentally determined rate law:
Rate = k[NO2]2
where k = 400 L mol-1 s-1
How long (in seconds) would it take for a sample of NO2
with an initial concentration of 0.50 M to decrease to a
concentration of 0.010 M?
USE THE FOLLOWING INFORMATION TO ANSWER THE NEXT
TWO (2) QUESTIONS.
2H2O2(aq) -->
2H2O(l) + O2(g)
The experimentally determined rate law is:
Rate = (0.056 s-1)[H2O2]
- If the initial concentration of H2O2
is 3.0 M, calculate the half-life (in seconds) for this
reaction.
- If the initial concentration of H2O2
is 3.0 M, calculate the concentration of H2O2
(in M) after 3.0 minutes.
- Collision theory is used to explain how chemical species
undergo a reaction. Using this theory and the kinetic
molecular model, which of the following does NOT
influence the rate of a chemical reaction?
- The temperature of the system.
- The geometry or orientation of the collision.
- The velocity of the reactants at the point of
collision.
- The concentrations of the reactants.
- All of the above influence the rate.
- According to collision theory, which of the following is NOT
a true statement concerning a catalyst?
- A catalyst changes the temperature of a reaction.
- The mechanism of a reaction will change when a
catalyst is added.
- A catalyst provides a different activation energy
for a reaction.
- A catalyst changes the speed of a reaction, but
not the equilibrium constant.
USE THE FOLLOWING INFORMATION TO ANSWER THE NEXT
THREE (3) QUESTIONS.
Mnn+
Tl+ + 2Ce4+ -------> Tl3+ + 2Ce3+
The experimentally determined rate law is:
Rate = k[Ce4+][Mn2+]
with the following proposed mechanism involving ions
of manganese:
Step 1: |
Ce4+ + Mn2+
--> Ce3+ + Mn3+ |
Step 2: |
Ce4+ + Mn3+
--> Ce3+ + Mn4+ |
Step 3: |
Tl+ + Mn4+
--> Tl3+ + Mn2+ |
- Which ion of manganese is the catalyst according to the
information provided above?
- Mn4+
- Mn3+
- Mn2+
- All of the above.
- There is not enough information provided to
answer the question.
- Which step in the proposed mechanism is the rate-limiting
step?
- Step 1
- Step 2
- Step 3
- All of the above.
- There is not enough information provided to
answer the question.
- What is the overall order of the reaction?
- 0
- 1
- 2
- 3
- 4
- Consider the following reaction in aqueous solution,
I-(aq) + OCl-(aq) -->
IO-(aq) + Cl-(aq)
and the following initial concentration and initial
rate data for this reaction,
[I-], M |
[OCl-], M |
initial rate, M s-1 |
0.1000 |
0.0500 |
3.05 x 10-4 |
0.3000 |
0.0100 |
1.83 x 10-4 |
0.2000 |
0.0500 |
6.10 x 10-4 |
0.3000 |
0.0200 |
3.66 x 10-4 |
Which of the following is the correct
rate law for this reaction?
- Rate = k[I-]
- Rate = k[OCl-]
- Rate = k[I-]2
- Rate = k[I-]2[OCl-]
- Rate = k[I-][OCl-]
- Which of the following CANNOT be affected/changed
by a catalyst?
- the mechanism of the reaction
- the spontaneity of the reaction
- the rate of the reaction
- the activation energy of the reaction
- all of the above can be affected/changed by a
catalyst
- Which of the following statements is TRUE?
- Rate constants can have negative values.
- The order of a reactant appearing in the rate law
must always be a positive integer.
- The order of each reactant appearing in the rate
law is equal to the stoichiometric coefficient
for that reactant in the overall balanced
equation.
- Reaction rates can have negative values.
- The rate of disappearance of a reactant is
generally not constant over time.
- Consider the bromination of acetone, CH3COCH3,
in the presence of acid,
CH3COCH3(aq)
+ Br2(aq) + H+(aq) CH3COCH2Br(aq)
and the following initial rate data:
[CH3COCH3], M |
[Br2], M |
[H+], M |
initial rate, M s-1 |
0.30 |
0.050 |
0.050 |
5.70 x 10-5 |
0.30 |
0.10 |
0.050 |
5.70 x 10-5 |
0.30 |
0.050 |
0.10 |
1.14 x 10-4 |
0.60 |
0.050 |
0.20 |
4.56 x 10-4 |
0.60 |
0.050 |
0.050 |
1.14 x 10-4 |
Which of the following is the correct
rate law for this reaction?
- Rate = k[CH3COCH3][Br2][H+]
- Rate = k[CH3COCH3]2[Br2]2[H+]
- Rate = k[CH3COCH3][Br2]
- Rate = k[CH3COCH3][H+]
- Rate = k[CH3COCH3]
- The following data were obtained for the gas-phase
decomposition of hydrogen iodide, HI, at 400oC,
2HI(g) --> H2(g) + I2(g)
time, sec |
[HI], M |
0 |
1.000 |
100 |
0.899 |
200 |
0.806 |
300 |
0.735 |
400 |
0.676 |
Calculate the concentration (in M) of
HI after 1100 seconds.
- The study of chemical kinetics can provide information
about which of the following?
- rates of chemical reactions
- reaction mechanisms
- factors that influence rates of chemical
reactions
- i only
- i and ii
- i and iii
- ii and iii
- i, ii and iii
- The reaction in which NO2(g) forms N2O4(g)
is second order in NO2,
2NO2(g)
--> N2O4(g)
Calculate the value of the rate constant for this
reaction if it takes 0.005 seconds for the initial
concentration of NO2 to decrease from 0.50 M
to 0.25 M.
- Consider the following reaction and experimental data,
2NO2(g) --> N2(g)
+ 2O2(g)
k, M-1 s-1 |
temperature, K |
0.522 |
319 |
0.755 |
329 |
1.70 |
352 |
4.02 |
381 |
5.03 |
389 |
Calculate the value (in kJ/mol) of the
activation energy for this reaction.
- An INCREASE in which of the following will not
produce an increase in the rate of a chemical reaction?
- activation energy
- temperature
- reactant concentration
- An increase in any of these will increase the
rate.
- Rate will not be affected by any of these.
- Which of the following would DECREASE the rate of
a chemical reaction?
- decreasing the activation energy
- increasing the concentrations of the reactants
- increasing the temperature
- adding a catalyst
- None of these will decrease the rate.
- The rate of the reaction,
S2-
+ 4 Cl2 + 8 OH- --> 8 Cl-
+ SO42- + 4 H2O
is measured at a particular moment in time and it is
found that -
[S2-]/
t = 2.0 x 10-2
mol L-1 s-1. At this same moment in
time, what is the rate (in mol L-1 s-1)
at which Cl- is being formed?
- For the reaction,
BH4-(aq)
+ 4 H2O(l) --> B(OH)4-(aq)
+ 4 H2(g)
the following data were obtained:
time, h |
[BH4-], M |
0 |
0.100 |
24 |
0.088 |
48 |
0.077 |
72 |
0.068 |
96 |
0.060 |
Calculate the value of the rate
constant for this reaction if the rate law is: Rate = k[BH4-].
- Consider the following reaction at 25oC,
2A --> B + C
where the initial concentration of A is 0.48 M.
Assuming that this reaction is second-order in A,
calculate how long (in seconds) it would take for the
concentration of A to reach 0.24 M if A is initially
decomposing (i.e., at t = 0) at a rate of 4.0 x 103
mol L-1 s-1.
- Which of the following statements is TRUE? For a
fast reaction,
- the values of the rate constant and the half-life
are both large.
- the values of the rate constant and the half-life
are both small.
- the value of the rate constant is small and the
value of the half-life is large.
- the value of the rate constant is large and the
value of the half-life is small.
- it is not possible to determine the values of the
rate constant or the half-life.
- What is an appropriate rate law for the following
reaction?
2 NO(g) + O2(g) -->
2 NO2(g)
- Rate = k(NO)2
- Rate = k(NO)2(O2)
- Rate = k(NO2)2
- Rate = K(O2)
- Cannot be determined from the information given.
- The rate of a zero order reaction:
- increases as reactant is consumed.
- is independent of temperature.
- depends on the concentration of the products.
- decreases as reactant is consumed.
- is independent of concentration of reactants or
products.
USE THE REACTION AND DATA BELOW TO ANSWER THE NEXT
FOUR (4) QUESTIONS.
NO(g) + O3(g) --> NO2(g)
+ O2(g)
|
initial [NO], M |
initial [O3], M |
initial rate of reaction, M s-1 |
trial 1 |
2.1 x 10-6 |
2.1 x 10-6 |
1.6 x 10-5 |
trial 2 |
4.2 x 10-6 |
2.1 x 10-6 |
3.2 x 10-5 |
trial 3 |
6.3 x 10-6 |
2.1 x 10-6 |
4.8 x 10-5 |
trial 4 |
6.3 x 10-6 |
4.2 x 10-6 |
9.6 x 10-5 |
trial 5 |
6.3 x 10-6 |
6.3 x 10-6 |
14.4 x 10-5 |
- The experimental rate law for the reaction is:
- Zero order in NO and first order in O3.
- First order in NO and first order in O3.
- Second order in NO and zero order in O3.
- Second order in NO and second order in O3.
- Independent of the concentration of O3.
- An acceptable value for the rate constant of this
reaction is:
- 6.7 x 10-5
- 7.6
- 3.6 x 106
- 1.8 x 1012
- 8.2 x 1017
- You prepare another trial in which the initial (NO) is 3.15
x 10-6 mol/L and the initial (O3)
is 3.15 x 10-6 mol/L. You predict that the
initial rate of reaction will be:
- 3.11 x 10-16 mol/L s
- 7.54 x 10-11 mol/L s
- 1.98 x 101 mol/L s
- 9.95 mol/L s
- 3.6 x 10-5 mol/L s
- A plot of (NO) vs. time would most closely resemble a:
- straight line with a positive shape.
- curve in which the (NO) decreases rapidly at
first and then slows down until a minimum
concentration is achieved.
- straight line with a negative slope.
- straight line with a slope of zero.
- curve in which the (NO) increases rapidly at
first and then slows down until a maximum
concentration is achieved.
- Which of the following expressions correctly describes
the relationship between the rates at which NO2
and Cl2 are consumed in the reaction below?
2 NO2(g) + Cl2(g) -->
2 NO2Cl(g)
- The following reaction is first-order in N2O3
and has a half-life of 19.25 minutes:
N2O5(g)
--> 2 NO2(g) + 1/2 O2(g)
How long will it take for the concentration of N2O5
to decrease from 0.050 mol/L to 0.030 mol/L?
- 2.41 minutes
- 3.60 minutes
- 9.63 minutes
- 14.3 minutes
- 19.3 minutes
USE THE REACTION AND DATA BELOW TO ANSWER THE NEXT
THREE (3) QUESTIONS.
2 N2O5(g) -->
4 NO2(g) + O2(g)
[N2O5], M |
time, s |
5.00 |
0 |
3.52 |
500 |
2.48 |
1000 |
1.75 |
1500 |
1.23 |
2000 |
- The rate law for this reaction is:
- zero-order in N2O5.
- half-order in N2O5.
- first-order in N2O5.
- second-order in N2O5.
- third-order in N2O5.
- The half-life for this reaction is:
- between 0 and 12 seconds.
- between 12 and 20 seconds.
- between 120 and 1,200 seconds.
- between 1,200 and 12,000 seconds.
- between 12,000 and 120,000 seconds.
- The concentration of N2O5 after 5,000
seconds is:
- between 0.001 and 0.010 mol/L
- between 0.010 and 0.10 mol/L
- between 0.10 and 0.4 mol/L
- between 0.4 and 0.8 mol/L
- between 0.8 and 1.2 mol/L
- Results of a 1985 analysis of a piece of parchment
indicated that 97.6% of the carbon-14 that was present
initially still remained in the sample. With which of the
following battles is this sample likely to be associated?
The rate constant (k) for the first-order decay of carbon-14
is 1.21 x 10-4/year.
- Battle of Actium in 31 BC, Octavian defeating
Mark Anthony.
- Battle of Lugdunum (Lyon), 197 AD, Septimius
Severus defeating Clodius Albinus.
- Battle of Hastings, 1066 AD, William of Normandy
defeating Harold II of England.
- Battle of Yorktown, 1781 AD, the Marquis de
Lafayette defeating Lord Cornwallis.
- Battle of Waterloo, 1815 AD, the Duke of
Wellington defeating Napoleon Bonaparte.
- The following reaction and rate law have been experimentally
determined:
2 NO2(g) + F2(g)
--> 2 NO2F(g), rate = k(NO2)(F2)
Which of the following mechanisms provides the best
explanation of the experimental rate law?
(a) 2NO2 + F2 --> 2NO2F (one step)
(b) NO2 + F2 --> NO2F + F (fast)
NO2 + F --> NO2F (slow)
(c) F2 --> 2F (slow)
2NO2 + 2F --> 2NO2F (fast)
(d) NO2 + F2 --> NO2F + F (slow)
NO2 + F --> NO2F (fast)
(e) None of these mechanisms are consistent with the experimental data.
- Nitrogen monoxide, NO, reacts with ozone, O3,
to produce nitrogen dioxide, NO2, and oxygen,
O2,
NO (g) + O3 (g)
-> NO2 (g) + O2 (g)
Consider the following mechanism for this reaction:
(1) |
O3(g) -> O2(g)
+ O(g) |
slow |
(2) |
NO(g) + O(g) -> NO2(g) |
fast |
Which one of the following rate laws
would be consistent with the mechanism proposed above?
- Rate = k[NO][O][O3]
- Rate = k[NO]
- Rate = k[NO][O3]
- Rate = k[NO][O]
- Rate = k[O3]
- For the mechanism described in the previous question,
which species are intermediates?
- O and NO
- NO and O3
- NO only
- O only
- NO2 only
- Nitrogen monoxide, NO, reacts with hydrogen, H2,
to produce nitrogen, N2, and water, H2O,
2 NO (g) + 2 H2 (g) -> N2
(g) + 2 H2O (g)
Consider the following mechanism for this reaction:
(1) |
2NO(g) <=> N2O2(g) |
fast |
(2) |
N2O2(g)
+ H2(g) -> N2O(g) + H2O(g) |
slow |
(3) |
N2O(g) + H2(g)
-> N2(g) + H2O(g) |
fast |
Which one of the following rate laws
would be consistent with the mechanism proposed above?
- Rate = k[NO]2[H2]2
- Rate = k[NO][H2]
- Rate = k[H2]2[N2]
- Rate = k[NO]2[H2]
- Rate = k[NO]2
- A particular chemical reaction involves a single reactant.
What is the order of the reaction if the rate increases
by a factor of eight when the concentration of the
reactant is doubled?
- zero order
- first order
- second order
- third order
- fourth order
- Consider the reaction,
2 N2O5
(g) -> 4 NO2 (g) + O2 (g)
and the following experimental data:
[N2O5], M |
rate, M s-1 |
0.100 |
6.96 x 10-4 |
0.050 |
3.48 x 10-4 |
0.025 |
1.74 x 10-4 |
What is the value of the rate constant,
k, for this reaction?
- Hydrogen sulfide (H2S) reacts with oxygen gas
according to the following equation:
2
H2S(g) + O2(g) --> 2 S(s) + 2 H2O(l)
Which of the following statements is TRUE?
- The reaction is 3rd order overall.
- The rate law is given by rate = k[H2S]2[O2].
- The reaction is 2nd order overall.
- The rate law is given by rate = k[H2S][O2].
- The rate law cannot be determined from the
information given.
- The following data were collected for the decay of HO2
radicals:
time, s |
[HO2], molecules cm-3 |
ln [HO2] |
1/[HO2] |
0 |
1.0000 x 1011 |
25.3 |
1 x 10-11 |
2 |
0.5000 x 1011 |
24.6 |
2 x 10-11 |
6 |
0.2500 x 1011 |
23.9 |
4 x 10-11 |
14 |
0.1250 x 1011 |
23.2 |
8 x 10-11 |
30 |
6.225 x 109 |
22.6 |
1.6 x 10-10 |
These data indicate that the decay of
HO2 occurs by a second order process BECAUSE:
- A plot of 1/[HO2] versus time is
linear with a slope of positive k.
- The half-life of the reaction is 2 seconds.
- A plot of ln[HO2] versus time is
linear with a slope of positive k.
- The rate of the reaction increases with time.
- The plots of 1/[HO2] and ln[HO2]
versus time are both linear.
- Gaseous N2O5 decomposes according
to the following equation:
N2O5(g)
--> 2 NO2(g) + 1/2 O2(g)
The experimental rate law is -
[N2O5]/
t = k[N2O5].
At a certain temperature the rate constant is k = 5.0 x
10-4/second. In how many seconds will the
concentration of N2O5 decrease to
one-tenth of its initial value?
- 2.0 x 103 seconds
- 4.6 x 103 seconds
- 2.1 x 102 seconds
- 1.4 x 103 seconds
- 5.0 x 10-3 seconds
- The gas phase reaction of nitrogen dioxide and carbon
monoxide given below was found by experiment to be second-order
with respect to NO2 and zero-order with
respect to CO below 25oC.
NO2(g)
+ CO(g) --> NO(g) + CO2(g)
Which of the following mechanisms is consistent with
these data?
- NO2 + 2 CO <=> N + 2 CO2,
(fast)
N + NO2 --> 2 NO, (slow)
- NO2 + 2 CO <=> N + 2 CO, (slow)
N + NO2 --> 2 NO, (fast)
- NO2 + NO2 <=> NO3
+ NO, (fast)
NO3 + CO --> NO2 + CO2,
(slow)
- NO2 + NO2 --> NO3
+ NO, (slow)
NO3 + CO --> NO2 + CO2,
(fast)
- With respect to the figure below, which choice correctly
identifies all of the numbered positions?
|
#1 |
#2 |
#3 |
#4 |
(a) |
catalyst |
catalyst |
activated complex |
product |
(b) |
reactants |
activated complex |
intermediate |
product |
(c) |
reactants |
activated complex |
catalyst |
product |
(d) |
reactants |
intermediate |
activated complex |
product |
(e) |
reactants |
intermediate |
activated complex |
catalyst |
- According to collision theory, not all collisions between
molecules lead to reaction. Which of the following
statements provide reasons why this is so?
- The total energy of the two colliding molecules
is less than some minimum amount of energy.
- Molecules cannot react with each other unless a
catalyst is present.
- Molecules that are improperly oriented during
collision will not react.
- Molecules in different states of matter cannot
react with each other.
- 1 and 2
- 1 and 3
- 2 and 3
- 1 and 4
- 3 and 4
- What potential problem, discussed in lecture, can be
avoided by using the "Method of Initial Rates"
for kinetic studies?
- Endothermic reactions.
- Reactions performed at low temperature.
- Equilibrium reactions.
- Non-spontaneous reactions.
- Reactions with large activation energies.
- For the reaction of ethyl bromide, CH3CH2Br,
with hydroxide ion, OH-, to produce ethyl
alcohol, CH3CH2OH, and bromide ion,
Br-,
CH3CH2Br
+ OH- --> CH3CH2OH +
Br-
the form of the rate law is:
Rate = k[CH3CH2Br][OH-]
Which of the following are the correct units for the
rate constant, k?
- s-1
- mol L-1 s-1
- L mol-1 s-1
- L2 mol-2 s-1
- L3 mol-3 s-1
- Consider a third-order reaction which involves a single
reactant. If the concentration of the reactant is
doubled, the rate of the reaction will:
- increase by a factor of two.
- increase by a factor of four.
- increase by a factor of eight.
- increase by a factor of nine.
- remain the same.
- In aqueous solution, the permanganate ion, MnO4-,
reacts with nitrous acid, HNO2, as follows:
2 MnO4- (aq) + 5 HNO2
(aq) + H+ (aq) --> 2 Mn2+ (aq) +
5 NO3- (aq) + 3 H2O (l)
Calculate the rate (in M s-1) at which the
HNO2 concentration is decreasing if the MnO4-
is decreasing at a rate of 0.024 M s-1.
- In lecture, we used the reaction of permanganate ion, MnO4-,
with oxalic acid, H2C2O4,
to study the effects of various changes upon the rate of
this reaction (these were the solutions that went from
purple to colorless):
2 MnO4-
(aq) + 5 H2C2O4 (aq) + 6
H+ (aq) --> 2 Mn2+ (aq) + 10 CO2
(g) + 8 H2O (l)
Consider the following initial concentration and
initial rate data for this reaction:
[MnO4-], M |
[H2C2O4], M |
[H+], M |
initial rate, M s-1 |
0.0010 |
0.0035 |
0.0010 |
7.0 x 10-4 |
0.0020 |
0.0035 |
0.0010 |
2.8 x 10-3 |
0.0020 |
0.0070 |
0.0010 |
5.6 x 10-3 |
0.0020 |
0.0070 |
0.0020 |
5.6 x 10-3 |
Calculate the value of the rate
constant, k, for this reaction.
- Laughing gas, N2O, can be prepared (ha, ha!)
from H2 and NO:
H2
(g) + 2 NO (g) -> N2O (g) + H2O
(g)
A study of initial concentrations (ha, ha!) versus
initial rate at a certain temperature yields the
following data for this reaction (ha, ha!):
[H2], M |
[NO], M |
initial rate, M s-1 |
0.1000 |
0.5000 |
2.560 x 10-6 |
0.2000 |
0.3000 |
1.843 x 10-6 |
0.1000 |
0.3000 |
9.216 x 10-7 |
0.2000 |
0.6000 |
7.373 x 10-6 |
Calculate the value of the rate
constant for this reaction (ha, ha!).
- The rate constant of a first-order reaction is 4.60 x 10-4/s
at 350oC. If the activation energy is 104 kJ/mol,
at what temperature will the rate constant be 8.80 x 10-4/s?
- 669oC
- 402oC
- 371oC
- 350oC
- 183oC
- Consider the following reaction at 500 K,
2C4H6(g) --> C8H12(g)
and the experimental data shown below,
[C4H6], M |
rate, M s-1 |
1.6 x 10-2 |
3.58 x 10-6 |
8.0 x 10-3 |
8.96 x 10-7 |
4.0 x 10-3 |
2.24 x 10-7 |
2.0 x 10-3 |
5.60 x 10-8 |
The order of the reaction with respect
to C4H6 is:
- half order.
- first order.
- second order.
- third order.
- fourth order.
- At 350 K, a particular second-order reaction, consisting
of a single reactant, A, has a rate constant equal
to 4.5 x 10-3 M-1 s-1.
If the initial concentration of A is 0.80 M, how
many half-lives are required for the concentration of A
to become equal to 0.10 M?
- 1 half-life
- 2 half-lives
- 3 half-lives
- 4 half-lives
- 5 half-lives
- The rate of the reaction
NO2(g)
+ CO(g) --> NO(g) + CO2(g)
depends only on the concentration of NO2
below 225oC. At a temperature below 225oC,
the following data were obtained.
time, s |
[NO2], M |
0 |
1.000 |
3.00 x 103 |
0.613 |
9.00 x 103 |
0.346 |
2.00 x 104 |
0.192 |
5.00 x 104 |
0.087 |
9.00 x 104 |
0.050 |
Calculate the value of the rate
constant for this reaction.